3x^2=264

Solution for 3x^2=264 equation:

3x^2=264

We move all terms to the left:

3x^2-(264)=0

a = 3; b = 0; c = -264;
Δ = b2-4ac
Δ = 02-4·3·(-264)
Δ = 3168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3168}=\sqrt{144*22}=\sqrt{144}*\sqrt{22}=12\sqrt{22}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{22}}{2*3}=\frac{0-12\sqrt{22}}{6}
=-\frac{12\sqrt{22}}{6}
=-2\sqrt{22}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{22}}{2*3}=\frac{0+12\sqrt{22}}{6}
=\frac{12\sqrt{22}}{6}
=2\sqrt{22}
$